规则枚举

一些简单的猜想实现,用来去除ifelse或者switch,虽然在jdk17中已经引入了新的switch语法,但是还是想做一些尝试

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package com.tthk.inland.ticket.core.enums.czloworder;

import lombok.AllArgsConstructor;
import lombok.Getter;

import java.util.Arrays;

/**
* @author Foam
* @Description 枚举
* @date 2023/5/4 17:12
*/
@Getter
@AllArgsConstructor
public enum LowOrderEnums {
UNLIMITED("枚举1"){
@Override
public boolean check(Integer id) {
return id<1;
}
},
ENUM2("枚举2"){
@Override
public boolean check(Integer id) {
return id >= 1 && id < 3;
}
},
ENUM3("枚举3"){
@Override
public boolean check(Integer id) {
return id > 3;
}
};
private String name;

public abstract boolean check(Integer id);

public static String getEnums(Integer id){
return Arrays.stream(LowOrderEnums.values()).filter(x -> x.check(id)).findFirst().map(LowOrderEnums::getName).orElse(id+"");
}

public static void main(String[] args) {
System.out.println(getEnums(1));
System.out.println(getEnums(2));
System.out.println(getEnums(3));
System.out.println(getEnums(4));
}
}

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package com.tthk.inland.ticket.core.enums.czloworder;

import lombok.AllArgsConstructor;
import lombok.Getter;

import java.util.Arrays;
import java.util.function.Predicate;

/**
* @author Foam
* @Description 枚举
* @date 2023/5/4 17:12
*/
@Getter
@AllArgsConstructor
public enum LowOrderEnums {
UNLIMITED(x -> x < 1,"枚举1"),
ENUM2(x -> x >= 1 && x < 3,"枚举2"),
ENUM3(x -> x > 3,"枚举3");
private Predicate<Integer> accumulator;

private String name;

public static String getEnums(Integer id){
return Arrays.stream(LowOrderEnums.values()).filter(x -> x.getAccumulator().test(id)).findFirst().map(LowOrderEnums::getName).orElse("没匹配到");
}

public static void main(String[] args) {
System.out.println(getEnums(1));
System.out.println(getEnums(2));
System.out.println(getEnums(3));
System.out.println(getEnums(4));
}
}